码蹄杯语言基础：结构体（C语言）-Toy模板网

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⭐MT1558新生命

狼群新生了一只尊贵的艾尔法狼，请设计一个结构体，管理它的信息，信息包括名字，年龄，性别。

输入艾尔法狼宝宝的信息，然后再输出他的信息。

格式
输入格式：
输入名字性别为字符型，年龄整型

输出格式：
输出名字性别为字符型，年龄整型

#include<stdio.h>
struct information
{
    char name[50];
    int age;
    char sex;
} message;
int main()
{
    scanf("%s %d %c", message.name, &message.age, &message.sex);
    printf("%s %d %c\n", message.name, message.age, message.sex);
    return 0;
}

⭐MT1559幼儿园

幼儿园开学了，请帮老师设计一个结构体，管理宝宝们的信息，信息包括姓名，年龄，性别。

输入5个宝宝的信息，然后再输出他们的信息。

格式
输入格式：
输入分5行，姓名性别为字符型，年龄整型

输出格式：
输出1行

#include<stdio.h>
struct information
{
    char name[50];
    int age;
    char sex;
};
int main()
{
    struct information baby1;
    struct information baby2;
    struct information baby3;
    struct information baby4;
    struct information baby5;

    scanf("%s %d %c", baby1.name, &baby1.age, &baby1.sex);
    scanf("%s %d %c", baby2.name, &baby2.age, &baby2.sex);
    scanf("%s %d %c", baby3.name, &baby3.age, &baby3.sex);
    scanf("%s %d %c", baby4.name, &baby4.age, &baby4.sex);
    scanf("%s %d %c", baby5.name, &baby5.age, &baby5.sex);

    printf("%s %d %c ", baby1.name, baby1.age, baby1.sex);
    printf("%s %d %c ", baby2.name, baby2.age, baby2.sex);
    printf("%s %d %c ", baby3.name, baby3.age, baby3.sex);
    printf("%s %d %c ", baby4.name, baby4.age, baby4.sex);
    printf("%s %d %c ", baby5.name, baby5.age, baby5.sex);
    return 0;
}

⭐MT1562谁是先锋

攻城战要开始了，女王依依手里有4个黑骑士，女王依依要找出最强大的黑骑士作为先锋。

请设计一个结构体，管理他们的信息，信息包括姓名，攻击力。

输入他们信息，然后再输出先锋的信息。

格式
输入格式：
输入分4行，姓名为字符型，攻击力整型

输出格式：
输出分4行

#include<stdio.h>
struct information
{
    char name[50];
    int attack_power;
};

int main()
{
    struct information Knight1;
    struct information Knight2;
    struct information Knight3;
    struct information Knight4;

    scanf("%s %d", Knight1.name, &Knight1.attack_power);
    scanf("%s %d", Knight2.name, &Knight2.attack_power);
    scanf("%s %d", Knight3.name, &Knight3.attack_power);
    scanf("%s %d", Knight4.name, &Knight4.attack_power);

    if ((Knight1.attack_power > Knight2.attack_power) && (Knight3.attack_power > Knight4.attack_power))
    {
        if (Knight1.attack_power > Knight3.attack_power)
        {
            printf("%s %d", Knight1.name, Knight1.attack_power);
        }
        else
        {
            printf("%s %d", Knight3.name, Knight3.attack_power);
        }
    }
    else if ((Knight1.attack_power < Knight2.attack_power) && (Knight3.attack_power < Knight4.attack_power))
    {
        if (Knight2.attack_power > Knight4.attack_power)
        {
            printf("%s %d", Knight2.name, Knight2.attack_power);
        }
        else
        {
            printf("%s %d", Knight4.name, Knight4.attack_power);
        }
    }
    else if ((Knight1.attack_power > Knight2.attack_power) && (Knight3.attack_power < Knight4.attack_power))
    {
        if (Knight1.attack_power > Knight4.attack_power)
        {
            printf("%s %d", Knight1.name, Knight1.attack_power);
        }
        else
        {
            printf("%s %d", Knight4.name, Knight4.attack_power);
        }
    }
    else if ((Knight1.attack_power < Knight2.attack_power) && (Knight3.attack_power > Knight4.attack_power))
    {
        if (Knight2.attack_power > Knight3.attack_power)
        {
            printf("%s %d", Knight2.name, Knight2.attack_power);
        }
        else
        {
            printf("%s %d", Knight3.name, Knight3.attack_power);
        }
    }
    return 0;
}

⭐MT1563谁是胆小鬼

攻城战结束了，女王依依清点俘虏，发现跑掉了1个胆小的穴居人，女王依依要找出是谁跑掉了。斥候调查发现逃走的是一个攻击力最弱小的穴居人。

请设计一个结构体，管理穴居人俘虏的信息，信息包括姓名，攻击力。

输入4个俘虏的信息，然后再输出逃走的俘虏的信息。

格式
输入格式：
输入分4行，姓名为字符型，攻击力整型

输出格式：
输出分4行

#include<stdio.h>
struct information
{
    char name[50];
    int attack_power;
};
int main()
{
    struct information people1;
    struct information people2;
    struct information people3;
    struct information people4;

    scanf("%s %d", people1.name, &people1.attack_power);
    scanf("%s %d", people2.name, &people2.attack_power);
    scanf("%s %d", people3.name, &people3.attack_power);
    scanf("%s %d", people4.name, &people4.attack_power);

    if ((people1.attack_power < people2.attack_power) && (people3.attack_power < people4.attack_power))
    {
        if (people1.attack_power < people3.attack_power)
        {
            printf("%s %d", people1.name, people1.attack_power);
        }
        else
        {
            printf("%s %d", people3.name, people3.attack_power);
        }
    }
    else if ((people1.attack_power > people2.attack_power) && (people3.attack_power > people4.attack_power))
    {
        if (people2.attack_power < people4.attack_power)
        {
            printf("%s %d", people2.name, people2.attack_power);
        }
        else
        {
            printf("%s %d", people4.name, people4.attack_power);
        }
    }
    else if ((people1.attack_power < people2.attack_power) && (people3.attack_power > people4.attack_power))
    {
        if (people1.attack_power < people4.attack_power)
        {
            printf("%s %d", people1.name, people1.attack_power);
        }
        else
        {
            printf("%s %d", people4.name, people4.attack_power);
        }
    }
    else if ((people1.attack_power > people2.attack_power) && (people3.attack_power < people4.attack_power))
    {
        if (people2.attack_power < people3.attack_power)
        {
            printf("%s %d", people2.name, people2.attack_power);
        }
        else
        {
            printf("%s %d", people3.name, people3.attack_power);
        }
    }
    return 0;
}

⭐MT1564编程好难

小码哥买了3本编程书，他想先学最简单的，请帮他把最薄的书挑出来。请设计一个结构体，管理书籍的信息，信息包括种类，书名（不含空格），页数。输入书籍的信息，然后再输出最薄的书信息。

格式
输入格式：
按行输入种类，书名为字符型，价格整型

输出格式：
按行输出种类，书名为字符型，价格整型文章来源地址https://www.toymoban.com/news/detail-502656.html

#include<stdio.h>
struct Books
{
    char language[10];
    char name[30];
    int page;
};
int main()
{
    struct Books book1;
    struct Books book2;
    struct Books book3;

    scanf("%s %s %d", book1.language, book1.name, &book1.page);
    scanf("%s %s %d", book2.language, book2.name, &book2.page);
    scanf("%s %s %d", book3.language, book3.name, &book3.page);

    if (book1.page < book2.page && book1.page < book3.page)
    {
        printf("%s %s %d", book1.language, book1.name, book1.page);
    }
    else if (book2.page < book1.page && book2.page < book3.page)
    {
        printf("%s %s %d", book2.language, book2.name, book2.page);
    }
    else if (book3.page < book2.page && book3.page < book1.page)
    {
        printf("%s %s %d", book3.language, book3.name, book3.page);
    }

    return 0;
}