报错：参数导致JSON parse error: Cannot deserialize instance of `[Ljava.lang.String；` out of START

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问题复现场景：前端传参字符串数组，后端接收报错

后端代码示例

    @RequestMapping(value = "/setOptUserIdByCommentId", method = RequestMethod.POST)
    @ApiOperation("设置分办人")
    public void setOptUserIdByCommentId(@RequestBody String[] commentIds, String optUserId, String optUserName) {
        ....
    }

前端代码示例

this.$axios({
                method: "post",
                url: "/jd/comment/setOptUserIdByCommentId",
                data: {
                    commentids: ids,
                    optuserid: encodeURI(this.handleUserValue[1]),
                    optusername: encodeURI(this.optusername)
                },
            }).then((res) => {
                if (res.data.status == 0) {
                    this.$message.error(res.data.msg)
                    return
                }
                this.$message.success('设置成功！')
                this.dialogVisible = false;
            });

后端警告内容：

Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize instance of [Ljava.lang.String; out of START_OBJECT token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of [Ljava.lang.String; out of START_OBJECT token at [Source: (PushbackInputStream); line: 1, column: 1]]

报错：参数导致JSON parse error: Cannot deserialize instance of `[Ljava.lang.String；` out of START_OBJECT to,报错,json,java,开发语言

解决方法

根据后端idea中提示，json解析错误。前端将数组转化成json推送，后端使用字符串接收再进行处理就可以解决。文章来源地址https://www.toymoban.com/news/detail-600937.html

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