今天被这个方括号懵晕了，特此记录
例如： 去除输入字符串“1[2.3]4[ab,c]”中的所有方括号和逗号：
$ echo "1[2.3]4[ab,c]"|sed -e "s/[,\]\[]//g"
1[2.3]4[ab,c]
It doesn't work!
原因：Regular Expressions
The <right-square-bracket> ( ']' ) shall lose its special meaning and represent itself in a bracket expression if it occurs first in the list (after an initial <circumflex> ( '^' ), if any).
解决方案：关键是要把 ] 右方括号不加escape放在首位.
$ echo "1[2.3]4[ab,c]"|sed -e "s/[][,]//g"
12.34abc
$ echo "1[2.3]4[ab,c]"|sed -e "s/[]\[,]//g"
12.34abc
$ echo "1[2.3]4[ab,c]"|sed -e "s/[],[]//g"
12.34abc
The order of some characters is important:
-
-should be at the end like this-] -
[]should be like that[][other characters] -
'should be escaped like that'\'' - not begin with
^like in[^ - not begin with
[.[=[:and end with.]=]:] - not end with
$]
References:
regex - How to escape square closing bracket in sed - Stack Overflow文章来源：https://www.toymoban.com/news/detail-633937.html
Regular Expressions文章来源地址https://www.toymoban.com/news/detail-633937.html
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