Leetcode 1011. Capacity To Ship Packages Within D Days (Binary Search经典)-Toy模板网

这篇具有很好参考价值的文章主要介绍了Leetcode 1011. Capacity To Ship Packages Within D Days (Binary Search经典)。希望对大家有所帮助。如果存在错误或未考虑完全的地方，请大家不吝赐教，您也可以点击"举报违法"按钮提交疑问。

Capacity To Ship Packages Within D Days
Medium
8.6K
179
Companies
A conveyor belt has packages that must be shipped from one port to another within days days.

The ith package on the conveyor belt has a weight of weights[i]. Each day, we load the ship with packages on the conveyor belt (in the order given by weights). We may not load more weight than the maximum weight capacity of the ship.

Return the least weight capacity of the ship that will result in all the packages on the conveyor belt being shipped within days days.

Example 1:

Input: weights = [1,2,3,4,5,6,7,8,9,10], days = 5
Output: 15
Explanation: A ship capacity of 15 is the minimum to ship all the packages in 5 days like this:
1st day: 1, 2, 3, 4, 5
2nd day: 6, 7
3rd day: 8
4th day: 9
5th day: 10

Note that the cargo must be shipped in the order given, so using a ship of capacity 14 and splitting the packages into parts like (2, 3, 4, 5), (1, 6, 7), (8), (9), (10) is not allowed.
Example 2:

Input: weights = [3,2,2,4,1,4], days = 3
Output: 6
Explanation: A ship capacity of 6 is the minimum to ship all the packages in 3 days like this:
1st day: 3, 2
2nd day: 2, 4
3rd day: 1, 4
Example 3:

Input: weights = [1,2,3,1,1], days = 4
Output: 3
Explanation:
1st day: 1
2nd day: 2
3rd day: 3
4th day: 1, 1

Constraints:

1 <= days <= weights.length <= 5 * 104
1 <= weights[i] <= 500

解法1：binary search
注意：start 从weights的最大值开始，不要从1开始。因为capacity必须>=货物中的最大值。end其实也可以设为所有货物的weights之和。文章来源地址https://www.toymoban.com/news/detail-700749.html

class Solution {
public:
    int shipWithinDays(vector<int>& weights, int days) {
        int n = weights.size();
        int start = *max_element(weights.begin(), weights.end()), end = INT_MAX;
        while (start + 1 < end) {
            int mid = start + (end - start) / 2;
            if (daysNeeded(weights, mid) <= days) {
                end = mid;
            } else {
                start = mid;
            }
        }
        if (daysNeeded(weights, start) <= days) return start;
        return end;
    }
private:
    int daysNeeded(vector<int>& weights, int capacity) {
        int n = weights.size();
        int res = 0, load = 0;
        for (int i = 0; i < n; i++) {
            load += weights[i];
            if (load > capacity) {
                load = weights[i];
                res++;
            }
        }
        if (load > 0) res++;
        return res;
    }
};