数据结构和算法——数据结构

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目录

线性结构

 队列结构的队列

链表结构的队列

链表的面试题

单向链表应用场景

约瑟夫环问题

栈结构

中缀表达式

前缀表达式

后缀表达式

非线性结构

递归解决迷宫问题

递归解决八皇后问题


线性结构

顺序存储方式,顺序表

常见的顺序存储结构有:数组、队列、链表、栈

链式存储方式,链表

数组结构

队列结构的队列

队列可以使用数组结构或者链表结构来存储,先入先出,后进后出。

数组结构的队列:

public class Demo {
    public static void main(String[] args) {
        CircleArrayQueue arrayQueue = new CircleArrayQueue(3);
        char key;
        Scanner scanner = new Scanner(System.in);
        boolean loop = true;
        while (loop) {
            System.out.println("s(show):显示队列");
            System.out.println("e(exit):退出程序");
            System.out.println("a(add):添加数据到队列");
            System.out.println("g(get):从队列取出数据");
            System.out.println("h(head):查看队列头的数据");
            key = scanner.next().charAt(0);
            switch (key) {
                case 's':
                    arrayQueue.showQueue();
                    break;
                case 'a':
                    System.out.println("请输入一个数字");
                    int value = scanner.nextInt();
                    arrayQueue.addQueue(value);
                    break;
                case 'g':
                    try {
                        int res = arrayQueue.getQueue();
                        System.out.println("取出的数据为=" + res);
                    } catch (Exception e) {
                        System.out.println(e.getMessage());
                    }
                    break;
                case 'e':
                    loop = false;
                    scanner.close();
                    System.out.println("程序退出...");
                    break;
                case 'h':
                    try {
                        int res = arrayQueue.headQueue();
                        System.out.println("查看的数据为=" + res);
                    } catch (Exception e) {
                        System.out.println(e.getMessage());
                    }
                    break;
                default:
                    break;
            }
        }
    }
}

class CircleArrayQueue {
    private int maxSize;
    // 指向队列头的位置
    private int front;
    // 指向队列尾的数据的下一个的位置,它指向的队尾的数据代表有值的
    private int rear;
    private int[] arr;

    public CircleArrayQueue(int arrMaxSize) {
        // 实际上队列有maxSize个元素,因为空出了一个位置
        maxSize = arrMaxSize + 1;
        arr = new int[maxSize];
        front = rear = 0;
    }

    public boolean isFull() {
        return (rear + 1) % maxSize == front;
    }

    public boolean isEmpty() {
        return front == rear;
    }

    public void addQueue(int n) {
        if (isFull()) {
            System.out.println("队列为满,不能加入数据");
            return;
        }
        arr[rear] = n;
        rear++;
        if (rear % maxSize == 0) {
            rear = 0;
        }
    }

    public int getQueue() {
        if (isEmpty()) {
            throw new RuntimeException("队列为空,不能取值");
        }
        int res = arr[front];
        front++;
        if (front % maxSize == 0) {
            front = 0;
        }
        return res;
    }

    public void showQueue() {
        if (isEmpty()) {
            System.out.println("队列为空,没有数据");
            return;
        }
//        for (int i = front; i != rear; i = (i + 1) % maxSize) {
        for (int i = front; i < front + size(); i++) {
            System.out.printf("arr[%d]=%d\n", i % maxSize, arr[i % maxSize]);
        }
    }

    public int headQueue() {
        if (isEmpty()) {
            throw new RuntimeException("队列为空,没有头数据");
        }
        return arr[front];
    }

    private int size() {
        return (rear + maxSize - front) % maxSize;
    }
}

 栈结构

public class ArrayStackDemo {
    public static void main(String[] args) {
        ArrayStack stack = new ArrayStack(4);
        String key;
        boolean loop = true;
        Scanner scanner = new Scanner(System.in);
        while (loop) {
            System.out.println("show:表示显示栈");
            System.out.println("exit:表示退出栈");
            System.out.println("push:表示压栈");
            System.out.println("pop:表示出栈");
            System.out.println("请输入你的选择:");
            key = scanner.next();
            switch (key) {
                case "s":
                    stack.list();
                    break;
                case "e":
                    loop = false;
                    break;
                case "pu":
                    try {
                        System.out.println("请输入要压栈的数据");
                        int value = scanner.nextInt();
                        stack.push(value);
                    } catch (Exception e) {
                        System.out.println(e.getMessage());
                    }
                    break;
                case "po":
                    try {
                        System.out.println(stack.pop());
                    } catch (Exception e) {
                        System.out.println(e.getMessage());
                    }
                    break;
                default:
                    System.out.println("输入有误");
                    break;
            }
        }
        System.out.println("程序退出了...");
    }
}

class ArrayStack {
    private int maxSize;
    private int[] stack;
    private int top = -1;

    public ArrayStack(int maxSize) {
        this.maxSize = maxSize;
        stack = new int[maxSize];
    }

    public boolean isFull() {
        return top == maxSize - 1;
    }

    public boolean isEmpty() {
        return top == -1;
    }

    public void push(int value) {
        if (isFull()) {
            System.out.println("栈满");
            return;
        }
        top++;
        stack[top] = value;
    }

    public int pop() {
        if (isEmpty()) {
            throw new RuntimeException("栈空,没有数据");
        }
        int res = stack[top];
        top--;
        return res;
    }

    public void list() {
        if (isEmpty()) {
            System.out.println("栈空,没有数据");
            return;
        }
        for (int i = top; i >= 0; i--) {
            System.out.printf("a[%d]=%d\n", i, stack[i]);
        }
    }
}
中缀表达式

人阅读的表达式。用来实现一个简单的计算器:

数据结构和算法——数据结构,数据结构和算法,数据结构,算法,java,1024程序员节

public class Calculator {
    public static void main(String[] args) {
        String expression = "7*2*2-5+1-5+3-4";
        ArrayStack2 numStack = new ArrayStack2(10);
        ArrayStack2 operStack = new ArrayStack2(10);
        int index = 0;
        int num1 = 0;
        int num2 = 0;
        int oper = 0;
        int res = 0;
        char ch = ' ';
        while (true) {
            ch = expression.substring(index, index + 1).charAt(0);
            if (operStack.isOper(ch)) {
                if (!operStack.isEmpty()) {
                    if (operStack.priority(ch) <= operStack.priority(operStack.peek())) {
                        num1 = numStack.pop();
                        num2 = numStack.pop();
                        oper = operStack.pop();
                        res = numStack.cal(num1, num2, (char) oper);
                        numStack.push(res);
                        operStack.push(ch);
                    } else {
                        operStack.push(ch);
                    }
                } else {
                    operStack.push(ch);
                }
            } else {
                // numStack.push(ch - '0');
                int keepNum = ch - '0';
                while (index < expression.length() - 1) {
                    index++;
                    ch = expression.substring(index, index + 1).charAt(0);
                    if (!operStack.isOper(ch)) {
                        keepNum = keepNum * 10 + (ch - '0');
                    } else {
                        index--;
                        break;
                    }
                }
                numStack.push(keepNum);
            }
            index++;
            if (index == expression.length()) {
                break;
            }
        }
        while (true) {
            if (operStack.isEmpty()) {
                break;
            }
            num1 = numStack.pop();
            num2 = numStack.pop();
            oper = operStack.pop();
            res = numStack.cal(num1, num2, (char) oper);
            numStack.push(res);
        }
        System.out.printf("表达式 %s = %d\n", expression, numStack.pop());
    }
}

class ArrayStack2 {
    private int maxSize;
    private int[] stack;
    private int top = -1;

    public ArrayStack2(int maxSize) {
        this.maxSize = maxSize;
        stack = new int[maxSize];
    }

    public boolean isFull() {
        return top == maxSize - 1;
    }

    public boolean isEmpty() {
        return top == -1;
    }

    public void push(int value) {
        if (isFull()) {
            System.out.println("栈满");
            return;
        }
        top++;
        stack[top] = value;
    }

    public int pop() {
        if (isEmpty()) {
            throw new RuntimeException("栈空,没有数据");
        }
        int res = stack[top];
        top--;
        return res;
    }

    public void list() {
        if (isEmpty()) {
            System.out.println("栈空,没有数据");
            return;
        }
        for (int i = top; i >= 0; i--) {
            System.out.printf("a[%d]=%d\n", i, stack[i]);
        }
    }

    public int priority(int oper) {
        if (oper == '*' || oper == '/') {
            return 1;
        } else if (oper == '+' || oper == '-') {
            return 0;
        }
        return -1;
    }

    public boolean isOper(char val) {
        return val == '+' || val == '-' || val == '*' || val == '/';
    }

    public int cal(int num1, int num2, char oper) {
        int res = 0;
        switch (oper) {
            case '+':
                res = num1 + num2;
                break;
            case '-':
                res = num2 - num1;
                break;
            case '*':
                res = num1 * num2;
                break;
            case '/':
                res = num2 / num1;
                break;
            default:
                break;
        }
        return res;
    }

    public int peek() {
        return stack[top];
    }
}
前缀表达式

也叫波兰表达式,(3+4)x5-6对应的前缀表达式为 - x + 3 4 5 6,从右向左扫描,遇到数字的时,将数字压入,遇到运算符时,弹出栈顶的两个数字进行计算,将结果压入栈,

后缀表达式

也叫逆波兰表达式,(3+4)x5-6 对应的逆波兰表达式为 3 4 + 5 x 6 - ,从左到右扫描,遇到数字把数字压栈,遇到运算符弹出栈顶的两个数字,进行运算,最后将结果压栈。可以用来写计算器:

代码:

public class PolandNotation {
    public static void main(String[] args) {
        // 逆波兰表达式
        // (3+4)*5-6
//        String suffixExpression = "3 4 + 5 * 6 -";
        // 4*5-8+60+8/2
        String suffixExpression = "4 5 * 8 - 60 + 8 2 / +";
        List<String> list = getListString(suffixExpression);
        int res = calculate(list);
    }

    public static List<String> getListString(String suffixExpression) {
        String[] s = suffixExpression.split(" ");
        List<String> list = new ArrayList<>();
        for (String ele : s) {
            list.add(ele);
        }
        return list;
    }

    public static int calculate(List<String> list) {
        Stack<String> stack = new Stack<>();
        for (String item : list) {
            if (item.matches("\\d+")) {
                stack.push(item);
            } else {
                int n2 = Integer.parseInt(stack.pop());
                int n1 = Integer.parseInt(stack.pop());
                int res = 0;
                if (item.equals("+")) {
                    res = n1 + n2;
                } else if (item.equals("-")) {
                    res = n1 - n2;
                } else if (item.equals("*")) {
                    res = n1 * n2;
                } else if (item.equals("/")) {
                    res = n1 / n2;
                } else {
                    throw new RuntimeException("运算符有误");
                }
                stack.push(res + "");
            }
        }
        return Integer.parseInt(stack.pop());
    }
}

如何中缀转后缀表达式:

1)初始化两个栈,运算符栈s1和存储中间结果的栈s2;

2)从左到右扫描中缀表达式;

3)遇到数时,压入栈s2;

4)遇到运算符时,比较其与栈s1栈顶的优先级:

1.如果栈s1为空,或栈顶运算符为左括号,则直接将此运算符压栈s1;

2.否则,若优先级比栈顶的高,也将运算符压入栈s1;

3.否则,将栈s1栈顶的运算符弹出并压入栈s2,再次(4 - 1)与 s1 中新的栈顶运算符比较;

5)遇到括号时:

1.如果是左括号,则直接压入栈s1;

2.如果是右括号,则依次弹出s1栈顶的运算符,并压入栈s2,直到遇到左括号为止,此时将一对括号丢弃;

6)重复步骤2至5,直到表达式最右边;

7)将s1中剩余的运算符依次弹出并压入栈s2;

8)依次弹出栈s2中的元素并输出,结果逆序即为中缀表达式对应的后缀表达式。

代码:

public class PolandNotation {
    public static void main(String[] args) {
        String expression = "1+((2+3)*4)-5"; // 后缀表达式:1 2 3 + 4 * + 5 -
        List<String> list = infixExpressionList(expression);
        List<String> result = parseSuffixExpreesionList(list);
    }

    public static List<String> parseSuffixExpreesionList(List<String> list) {
        Stack<String> s1 = new Stack<>(); // 运算符栈
        List<String> s2 = new ArrayList<>(); // 存储中间结果的栈
        for (String item : list) {
            if (item.matches("\\d+")) {
                s2.add(item);
            } else if (item.equals("(")) {
                s1.push(item);
            } else if (item.equals(")")) {
                while (!s1.peek().equals("(")) {
                    s2.add(s1.pop());
                }
                s1.pop(); // 弹栈 (
            } else {
                while (!s1.isEmpty() && Operation.getValue(s1.peek()) >= Operation.getValue(item)) {
                    s2.add(s1.pop());
                }
                s1.add(item);
            }
        }
        while (!s1.isEmpty()) {
            s2.add(s1.pop());
        }
        return s2;
    }

    private static List<String> infixExpressionList(String s) {
        ArrayList<String> list = new ArrayList<>();
        int i = 0;
        String str;
        char c;
        do {
            c = s.charAt(i);
            if (c < '0' || c > '9') {
                list.add("" + c);
                i++;
            } else {
                str = "";
                while (i < s.length() && (c = s.charAt(i)) >= '0' && c <= '9') {
                    str += c;
                    i++;
                }
                list.add(str);
            }
        } while (i < s.length());
        return list;
    }
}

class Operation {
    private static int ADD = 1;
    private static int SUB = 1;
    private static int MUL = 1;
    private static int DIV = 1;

    public static int getValue(String operation) {
        int result = 0;
        switch (operation) {
            case "+":
                result = ADD;
                break;
            case "-":
                result = SUB;
                break;
            case "*":
                result = MUL;
                break;
            case "/":
                result = DIV;
                break;
            default:
                System.out.println("不存在该运算符");
                break;
        }
        return result;
    }
}

链表结构的队列

public class SingleLinkListDemo {
    public static void main(String[] args) {
        HeroNode hero1 = new HeroNode(1, "宋江", "及时雨");
        HeroNode hero2 = new HeroNode(2, "卢俊义", "玉麒麟");
        HeroNode hero3 = new HeroNode(3, "吴用", "智多星");
        SingleLinkList singleLinkList = new SingleLinkList();
        singleLinkList.add(hero3);
        singleLinkList.add(hero2);
        singleLinkList.add(hero1);
//        singleLinkList.add(hero3);
//        HeroNode newHero = new HeroNode(3, "张三", "法外狂徒");
//        singleLinkList.update(newHero);
        HeroNode delHero1 = new HeroNode(1, "", "");
        singleLinkList.del(delHero1);
        singleLinkList.reverse();
        singleLinkList.list();
    }
}

class SingleLinkList {
    private HeroNode headNode = new HeroNode(0, "", "");

    // 非递归反转
    public void reverse3() {
        if (headNode.getNext() == null || headNode.getNext().getNext() == null) {
            return;
        }
        HeroNode nextNode1, nextNode2, nextNode3;
        nextNode1 = headNode.getNext();
        nextNode2 = nextNode1.getNext();
        nextNode3 = nextNode2.getNext();
        nextNode2.setNext(nextNode1);
        nextNode1.setNext(null);

        while (nextNode3 != null) {
            nextNode1 = nextNode2;
            nextNode2 = nextNode3;
            nextNode3 = nextNode3.getNext();
            nextNode2.setNext(nextNode1);
        }
        headNode.setNext(nextNode2);
    }

    // 递归反转
    public void reverse() {
        HeroNode nextNode = headNode.getNext();
        headNode.setNext(reverse2(headNode.getNext()));
        nextNode.setNext(null);
    }
    private HeroNode reverse2(HeroNode heroNode) {
        if (heroNode.getNext() != null) {
            HeroNode lastNode = reverse2(heroNode.getNext());
            heroNode.getNext().setNext(heroNode);
            return lastNode;
        }
        return heroNode;
    }

    public void del(HeroNode delHeroNode) {
        if (headNode.getNext() == null) {
            System.out.println("链表为空");
            return;
        }
        HeroNode preNode, nextNode;
        preNode = headNode;
        nextNode = headNode.getNext();
        while (nextNode != null) {
            if (nextNode.getNo() == delHeroNode.getNo()) {
                preNode.setNext(nextNode.getNext());
                // nextNode.setNext(null);
                return;
            }
            preNode = nextNode;
            nextNode = nextNode.getNext();
        }
        System.out.println("删除编号= " + delHeroNode.getNo() + " 的元素没有找到");
    }

    public void update(HeroNode newHeroNode) {
        if (headNode.getNext() == null) {
            System.out.println("链表为空");
            return;
        }
        HeroNode preNode, nextNode;
        preNode = headNode;
        nextNode = headNode.getNext();
        while (nextNode != null) {
            if (nextNode.getNo() == newHeroNode.getNo()) {
                newHeroNode.setNext(nextNode.getNext());
                preNode.setNext(newHeroNode);
                return;
            }
            preNode = nextNode;
            nextNode = nextNode.getNext();
        }
        System.out.println("编号= " + newHeroNode.getNo() + " 的元素没有找到");
    }

    public void add(HeroNode heroNode) {
        HeroNode nextNode, preNode;
        preNode = headNode;
        nextNode = headNode.getNext();
        // 头插法
        if (nextNode == null) {
            headNode.setNext(heroNode);
            heroNode.setNext(null);
            return;
        }
        // 中插法
        while (nextNode != null) {
            if (heroNode.getNo() < nextNode.getNo()) {
                preNode.setNext(heroNode);
                heroNode.setNext(nextNode);
                return;
            }
            // 相同的数据不能进行插入
            if (heroNode.getNo() == nextNode.getNo()) {
                System.out.println("编号=" + heroNode.getNo() + " 已存在,不能添加");
                return;
            }
            preNode = nextNode;
            nextNode = nextNode.getNext();
        }
        // 尾插法
        preNode.setNext(heroNode);
        heroNode.setNext(null);
    }

    public void list() {
        HeroNode tmpNode = headNode.getNext();
        if (tmpNode == null) {
            System.out.println("链表为空");
            return;
        }
        while (tmpNode != null) {
            System.out.println("node= " + tmpNode + " -->");
            tmpNode = tmpNode.getNext();
        }
    }
}

@Data
class HeroNode {
    private int no;
    private String name;
    private String nickName;
    private HeroNode next;

    public HeroNode(int hNo, String hName, String hNickName) {
        this.no = hNo;
        this.name = hName;
        this.nickName = hNickName;
    }

    @Override
    public String toString() {
        return "HeroNode{" +
                "no=" + no +
                ", name='" + name + '\'' +
                ", nickName='" + nickName + '\'' +
                '}';
    }
}

约瑟夫环问题

public class Josephu {
    public static void main(String[] args) {
        CircleSingleLinkedList list = new CircleSingleLinkedList();
        list.addBoy(5);
        list.countBoy(1, 2, 5);
//        list.showBoy();
    }
}

class CircleSingleLinkedList {
    private Boy first = null;

    public void addBoy(int nums) {
        if (nums < 2) {
            System.out.println("nums的值不正确");
            return;
        }
        Boy curBoy = null;
        for (int i = 0; i < nums; i++) {
            Boy boy = new Boy(i + 1);
            if (i == 0) {
                first = boy;
                first.setNext(first);
                curBoy = first;
            } else {
                curBoy.setNext(boy);
                boy.setNext(first);
                curBoy = boy;
            }
        }
    }

    public void showBoy() {
        if (first == null) {
            System.out.println("链表为空");
            return;
        }
        Boy curBoy = first;
        do {
            System.out.println("编号= " + curBoy.getNo() + " -->");
            curBoy = curBoy.getNext();
        } while (curBoy != first);
    }

    /**
     * @param startNo  从第几个开始
     * @param countNum 数几下
     * @param nums     最初有多少个小孩
     */
    public void countBoy(int startNo, int countNum, int nums) {
        if (first == null || startNo < 1 || startNo > nums) {
            System.out.println("参数输入有误,请重新输入");
            return;
        }
        Boy helper = first;
        while (helper.getNext() != first) {
            helper = helper.getNext();
        }
        for (int i = 0; i < startNo - 1; i++) {
            first = first.getNext();
            helper = helper.getNext();
        }
        while (helper != first) {
            for (int i = 0; i < countNum - 1; i++) {
                first = first.getNext();
                helper = helper.getNext();
            }
            System.out.println("小孩 " + first.getNo() + " 出圈");
            first = first.getNext();
            helper.setNext(first);
//            nums--;
        }
        System.out.println("最后留在圈中的小孩编号 " + first.getNo());
    }
}

class Boy {
    private int no;
    private Boy next;

    public Boy(int no) {
        this.no = no;
    }

    //#region get|set
    public int getNo() {
        return no;
    }

    public void setNo(int no) {
        this.no = no;
    }

    public Boy getNext() {
        return next;
    }

    public void setNext(Boy next) {
        this.next = next;
    }
    //#endregion
}

非线性结构

常见的非线性结构有:二维数组、多维数组、广义表、树结构、图结构。

图结构

递归解决迷宫问题

public class MiGong {
    public static void main(String[] args) {
        int[][] map = new int[8][7]; // 1 墙 0 未走 2 已走
        for (int i = 0; i < 7; i++) {
            map[0][i] = 1;
            map[7][i] = 1;
            map[i][0] = 1;
            map[i][6] = 1;
        }
        map[3][1] = 1;
        map[3][2] = 1;
        setWay(map, 1, 1);
    }

    public static boolean setWay(int[][] map, int i, int j) {
        if (map[6][5] == 2) {
            return true;
        } else {
            if (map[i][j] == 0) {
                map[i][j] = 2;
                if (setWay(map, i + 1, j)) { // 上
                    return true;
                } else if (setWay(map, i, j + 1)) { // 又
                    return true;
                } else if (setWay(map, i - 1, j)) { // 下
                    return true;
                } else if (setWay(map, i, j - 1)) { // 左
                    return true;
                } else {
                    map[i][j] = 3; // 已走未通过
                    return false;
                }
            } else {
                return false; // 值可能是 1、2、3
            }
        }
    }
}

递归解决八皇后问题

public class Queue8 {
    int max = 8;
    int[] array = new int[max];

    /**
     * 有几种解法
     **/
    int count = 0;
    // int judgeCount=0;

    public static void main(String[] args) {
        Queue8 queue8 = new Queue8();
        queue8.check(0);
        // System.out.println("解法count=" + queue8.count + "种");
    }

    /**
     * 放置第n个皇后
     *
     * @param n
     */
    private void check(int n) {
        if (n == max) {
            print();
            return;
        }
        for (int i = 0; i < max; i++) {
            array[n] = i;
            if (judge(n)) { // 不冲突
                check(n + 1);
            }
        }
    }

    /**
     * 是否与之前的皇后冲突
     *
     * @param n 第n个皇后,从0开始
     * @return
     */
    private boolean judge(int n) {
        // judgeCount++;
        for (int i = 0; i < n; i++) {
            if (array[i] == array[n] || Math.abs(n - i) == Math.abs(array[i] - array[n])) { // 同列 同斜线
                return false;
            }
        }
        return true;
    }

    private void print() {
        for (int i = 0; i < array.length; i++) {
            System.out.print(array[i] + " ");
        }
        System.out.println();
        count++;
    }
}

树结构

数据结构和算法——树结构-CSDN博客

增强的顺序结构

哈希表

是数组加链表的数据结构,用到了拉链法。

实例问题:

有一个公司,当有新员工来报道时,要求将该员工的信息加入(id,性别,年龄,住址...),当输入该员工的id时,要求查找到该员工的所有信息。

public class HashTableDemo {
    public static void main(String[] args) {
        HashTable hashTable = new HashTable(7);
        String key = "";
        Scanner scanner = new Scanner(System.in);
        boolean loop = true;
        while (loop) {
            System.out.println("add:添加雇员");
            System.out.println("list:显示雇员");
            System.out.println("find:查找雇员");
            System.out.println("del:删除雇员");
            System.out.println("exit:退出系统");
            key = scanner.nextLine();
            switch (key) {
                case "a":
                    System.out.println("输入id:");
                    int id = scanner.nextInt();
                    System.out.println("输入名字:");
                    String name = scanner.next();
                    Emp emp = new Emp(id, name);
                    hashTable.add(emp);
                    continue;
                case "l":
                    hashTable.list();
                    break;
                case "d":
                    System.out.println("输入id:");
                    id = scanner.nextInt();
                    hashTable.delEmpById(id);
                    break;
                case "f":
                    System.out.println("输入id:");
                    id = scanner.nextInt();
                    emp = hashTable.findEmpById(id);
                    if (emp == null) {
                        System.out.println("该雇员不存在");
                    } else {
                        System.out.println(emp);
                    }
                    break;
                case "e":
                    loop = false;
                    break;
                default:
                    loop = true;
                    break;
            }
        }
    }
}

class Emp {
    public int id;
    public String name;
    public Emp next;

    public Emp(int id, String name) {
        this.id = id;
        this.name = name;
        this.next = next;
    }

    @Override
    public String toString() {
        return "Emp{" +
                "id=" + id +
                ", name='" + name + '\'' +
                '}';
    }
}

class EmpLinkedList {
    private Emp head;

    public EmpLinkedList(Emp head) {
        this.head = head;
    }

    public void add(Emp emp) {
        if (head == null) {
            head = emp;
        } else {
            Emp curEmp = head;
            while (curEmp.next != null) {
                curEmp = curEmp.next;
            }
            curEmp.next = emp;
        }
    }

    public void list() {
        if (head == null) {
            System.out.println("当前链表为空");
            return;
        }
        System.out.println("当前链表的信息为:");
        Emp curEmp = head;
        while (curEmp != null) {
            System.out.println("emp= " + curEmp);
            curEmp = curEmp.next;
        }
    }

    public Emp findEmpById(int id) {
        Emp curEmp = head;
        while (curEmp != null) {
            if (curEmp.id == id) {
                return curEmp;
            }
            curEmp = curEmp.next;
        }
        return null;
    }

    public void delEmpById(int id) {
        if (head == null) {
            System.out.println("该雇员不存在");
            return;
        }
        if (head.id == id) {
            head = null;
            return;
        }
        Emp curEmp = head;
        while (curEmp.next != null) {
            if (curEmp.next.id == id) {
                curEmp.next = curEmp.next.next;
                System.out.println("删除雇员成功");
                return;
            }
            curEmp = curEmp.next;
        }
        System.out.println("该雇员不存在");
    }
}

class HashTable {
    private EmpLinkedList[] empListedListArray;
    private int size;

    public HashTable(int size) {
        this.size = size;
        this.empListedListArray = new EmpLinkedList[this.size];
    }

    public void add(Emp emp) {
        // 根据id得到下标
        int index = hashFun(emp.id);
        if (empListedListArray[index] == null) {
            EmpLinkedList empLinkedList = new EmpLinkedList(emp);
            empListedListArray[index] = empLinkedList;
        } else {
            empListedListArray[index].add(emp);
        }
    }

    public int hashFun(int id) {
        return id % this.size;
    }

    public void list() {
        for (int i = 0; i < this.size; i++) {
            EmpLinkedList empLinkedList = empListedListArray[i];
            if (empLinkedList != null) {
                empLinkedList.list();
                System.out.println("----------------");
            }
        }
    }

    public Emp findEmpById(int id) {
        int index = hashFun(id);
        if (empListedListArray[index] == null) {
            return null;
        }
        Emp emp = empListedListArray[index].findEmpById(id);
        return emp;
    }

    public void delEmpById(int id) {
        int index = hashFun(id);
        if (empListedListArray[index] == null) {
            System.out.println("该雇员不存在");
            return;
        }
        empListedListArray[index].delEmpById(id);
    }
}

数组加二叉树的结构。

参考教程视频:【尚硅谷】数据结构与算法(Java数据结构与算法)_哔哩哔哩_bilibili文章来源地址https://www.toymoban.com/news/detail-728660.html

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