JSON parse error: Unexpected character (‘ ‘ (code 160))-PostMan里面Json参数编码不一致解决方法-Toy模板网

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PostMan里面Json参数编码不一致解决方法

一：报错日志为JSON parse error: Unexpected character (’ ’ (code 160))

注意看==={Unexpected character (’ ’ (code 160))}

2023-07-18 16:35:57.624 ERROR 29624 --- [  XNIO-1 task-1] o.s.c.log.error.RestExceptionTranslator  : 消息不能读取:JSON parse error: Unexpected character (' ' (code 160)): was expecting double-quote to start field name; nested exception is com.fasterxml.jackson.core.JsonParseException: Unexpected character (' ' (code 160)): was expecting double-quote to start field name
 at [Source: (PushbackInputStream); line: 1, column: 4]
2023-07-18 16:38:07.334 ERROR 29624 --- [  XNIO-1 task-1] o.s.c.log.error.RestExceptionTranslator  : 消息不能读取:JSON parse error: Invalid UTF-8 start byte 0xa0; nested exception is com.fasterxml.jackson.core.JsonParseException: Invalid UTF-8 start byte 0xa0
 at [Source: (PushbackInputStream); line: 1, column: 23]
2023-07-18 16:40:06.600 ERROR 29624 --- [  XNIO-1 task-1] o.s.c.log.error.RestExceptionTranslator  : 消息不能读取:JSON parse error: Unexpected character (' ' (code 160)): was expecting double-quote to start field name; nested exception is com.fasterxml.jackson.core.JsonParseException: Unexpected character (' ' (code 160)): was expecting double-quote to start field name
 at [Source: (PushbackInputStream); line: 1, column: 46]

二：解决方法-如下图-点击右侧Beautify按钮将Json参数编码格式化

JSON parse error: Unexpected character (‘ ‘ (code 160))-PostMan里面Json参数编码不一致解决方法,java,json,postman 文章来源地址https://www.toymoban.com/news/detail-735254.html

三：再次请求-解决此问题

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