难度：简单
给你一个整数
n，找出从1到n各个整数的 Fizz Buzz 表示，并用字符串数组answer（下标从 1 开始）返回结果，其中：
answer[i] == "FizzBuzz"如果i同时是3和5的倍数。answer[i] == "Fizz"如果i是3的倍数。answer[i] == "Buzz"如果i是5的倍数。answer[i] == i（以字符串形式）如果上述条件全不满足。示例 1：
输入：n = 3 输出：["1","2","Fizz"]示例 2：
输入：n = 5 输出：["1","2","Fizz","4","Buzz"]示例 3：
输入：n = 15 输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]提示：文章来源：https://www.toymoban.com/news/detail-786965.html
1 <= n <= 104题解：
class Solution(object): def fizzBuzz(self, n): res = [] for i in range(1,n+1): # print(i) if i % 3== 0 and i %5 == 0: res.append('FizzBuzz') elif i%3 == 0: res.append('Fizz') elif i%5 == 0: res.append('Buzz') else: res.append(str(i)) return res
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