本专栏的目的是分享可以通过HDLBits仿真的Verilog代码 以提供参考 各位可同时参考我的代码和官方题解代码 或许会有所收益
题目链接:Count15 - HDLBits
module top_module (
input clk,
input reset, // Synchronous active-high reset
output [3:0] q
);
always @(posedge clk) begin
if (reset) q <= 0 ;
else q <= q == 15 ? 0 : q + 1 ;
end
endmodule
题目链接:Count10 - HDLBits
module top_module (
input clk,
input reset, // Synchronous active-high reset
output [3:0] q
);
always @(posedge clk) begin
if (reset) q <= 0 ;
else q <= q == 9 ? 0 : q + 1 ;
end
endmodule
题目链接:Count1to10 - HDLBits
module top_module (
input clk,
input reset, // Synchronous active-high reset
output reg [3:0] q
);
always @(posedge clk) begin
if (reset) q <= 1 ;
else q <= q == 10 ? 1 : q + 1 ;
end
endmodule
题目链接:Countslow - HDLBits
module top_module (
input clk,
input slowena,
input reset,
output reg [3:0] q
);
always @(posedge clk) begin
if (reset) q <= 0 ;
else if (slowena) q <= q == 9 ? 0 : q + 1 ;
else q <= q ;
end
endmodule
题目链接:Exams/ece241 2014 q7a - HDLBits
module top_module (
input clk,
input reset,
input enable,
output reg [3:0] Q,
output c_enable,
output c_load,
output [3:0] c_d
);
reg [3:0] cnt_4o ;
always @(posedge clk) begin
if (reset) Q <= 1 ;
else if (enable) Q <= Q == 12 ? 1 : Q + 1 ;
else Q <= Q ;
end
assign c_enable = enable ;
assign c_load = reset | (enable && Q == 12) ;
assign c_d = c_load ? 1 : 0 ;
count4 the_counter (clk, c_enable, c_load, c_d, cnt_4o);
endmodule
题目链接:Exams/ece241 2014 q7b - HDLBits
module top_module (
input clk,
input reset,
output OneHertz,
output [2:0] c_enable
);
reg [3:0] q0, q1, q2 ;
bcdcount counter0 (clk, reset, c_enable[0], q0);
bcdcount counter1 (clk, reset, c_enable[1], q1);
bcdcount counter2 (clk, reset, c_enable[2], q2);
assign c_enable = {q0 == 9 & q1 == 9, q0 == 9, 1'b1};
assign OneHertz = q2 == 9 & q1 == 9 & q0 == 9 ;
endmodule
题目链接:Countbcd - HDLBits文章来源:https://www.toymoban.com/news/detail-818969.html
module top_module (
input clk,
input reset, // Synchronous active-high reset
output [3:1] ena,
output reg [15:0] q
);
always @ (*) begin
if (q[3:0] == 9 && q[7:4] == 9 && q[11:8] == 9) ena = 7 ;
else if (q[3:0] == 9 && q[7:4] == 9) ena = 3 ;
else if (q[3:0] == 9) ena = 1 ;
else ena = 0 ;
end
sub_cnt u1(clk, reset, 1'b1, q[3:0]) ;
sub_cnt u2(clk, reset, ena[1], q[7:4]) ;
sub_cnt u3(clk, reset, ena[2], q[11:8]) ;
sub_cnt u4(clk, reset, ena[3], q[15:12]) ;
endmodule
module sub_cnt (
input clk,
input reset, // Synchronous active-high reset
input enable,
output reg [3:0] q
);
always @(posedge clk) begin
if (reset) q <= 0 ;
else if (enable) q <= q == 9 ? 0 : q + 1 ;
else q <= q ;
end
endmodule
题目链接:Count clock - HDLBits文章来源地址https://www.toymoban.com/news/detail-818969.html
module top_module(
input clk,
input reset,
input ena,
output reg pm,
output reg [7:0] hh,
output reg [7:0] mm,
output reg [7:0] ss
);
wire [2:0] enable ;
assign enable = {mm == 8'h59 & ss == 8'h59 & ena, ss == 8'h59 & ena, ena} ;
cnt60 uss(clk, reset, enable[0], ss) ;
cnt60 umm(clk, reset, enable[1], mm) ;
always @(posedge clk) begin
if (reset) begin
hh <= 8'h12 ;
pm <= 0 ;
end
else
if (enable[2])
if (hh == 8'h12) hh <= 8'h1 ;
else if (hh == 8'h11) begin
pm <= ~pm ;
hh[3:0] <= hh[3:0] + 1'h1 ;
end
else
if (hh[3:0] == 4'h9) begin
hh[3:0] <= 4'h0 ;
hh[7:4] <= hh[7:4] + 1'h1 ;
end
else
hh[3:0] <= hh[3:0] + 1'h1 ;
else
hh <= hh ;
end
endmodule
module cnt60(
input clk,
input reset,
input ena,
output reg [7:0] q
);
always @(posedge clk) begin
if (reset) q <= 8'h0 ;
else
if (ena)
if (q[3:0] == 4'h9)
if
(q[7:4] == 4'h5) q <= 8'h0 ;
else begin
q[7:4] <= q[7:4] + 1'h1 ;
q[3:0] <= 4'h0 ;
end
else
q[3:0] <= q[3:0] + 1'h1 ;
else
q <= q ;
end
endmodule
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