上一篇文章只实现了operator==操作符重载,由于运算符较多,该篇文章单独实现剩余所有的运算符重载。继续以Date类为例,实现运算符重载:
1.Date.h
#pragma once
#include <iostream>
#include <assert.h>
using namespace std;
class Date
{
private:
int _year;
int _month;
int _day;
public:
void Print();
Date(int yaer, int month, int day);
bool operator<(const Date& d);
bool operator<=(const Date& d);
bool operator>(const Date& d);
bool operator>=(const Date& d);
bool operator==(const Date& d);
bool operator!=(const Date& d);
//单独的用一个函数把每个月多少天,封装起来
int GetMonthDays(int year, int month)
{
assert(month > 0 && month < 13);
static int MonthDay[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };
if (month==2&&(year % 4 == 0 && year % 100 != 0))
{
return 29;
}
return MonthDay[month];
}
Date& operator+=(int day);
Date operator+(int day);
Date& operator-=(int day);
Date operator-(int day);
//++d,前置++
Date& operator++();
//d++,后置++
Date operator++(int);
//前置--
Date& operator--();
//后置--
Date operator--(int);
//两个日期相减:d1-d2
int operator-(const Date& d);
};
Date.cpp文章来源:https://www.toymoban.com/news/detail-829692.html
#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include "Date.h"
void Date::Print()
{
cout << _year << "/" << _month << "/" << _day << endl;
}
Date::Date(int year=1, int month=1, int day=1)
{
_year = year;
_month = month;
_day = day;
}
// 写好一个直接复用!!!
bool Date::operator<(const Date& d)
{
if (_year < d._year)
{
return true;
}
else if (_year == d._year)
{
if (_month < d._month)
return true;
else if ((_month == d._month) && (_day < d._day))
return true;
else
return false;
}
else
return false;
}
bool Date::operator==(const Date& d)
{
if ((_year == d._year) && (_month == d._month) && (_day == d._day))
return true;
else
return false;
}
bool Date::operator<=(const Date& d)
{
return *this == d || *this < d;
}
bool Date::operator>(const Date& d)
{
return !(*this <= d);
}
bool Date::operator>=(const Date& d)
{
return (*this > d || *this == d);
}
bool Date::operator!=(const Date& d)
{
return !(*this == d);
}
Date& Date::operator+=(int day)
{
_day += day;//先加
//这里是while,因为如果是if的话,如果一次加了很大的数据减一次不一定能减得完!!!
while(_day > GetMonthDays(_year, _month))
{
_day -= GetMonthDays(_year, _month);
++_month;
if (_month == 13)
{
++_year;
_month = 1;
}
}
return *this;
}
Date Date::operator+(int day)
{
Date tmp=*this;
tmp += day;
return tmp;
}
Date& Date::operator-=(int day)
{
_day -= day;
while (_day <= 0)
{
--_month;
if (_month == 0)
{
--_year;
_month = 12;
}
_day += GetMonthDays(_year, _month);
}
return *this;
}
Date Date::operator-(int day)
{
Date tmp = *this;
tmp -= day;
return tmp;
}
Date& Date::operator++()
{
return *this += 1;
}
Date Date::operator++(int)
{
Date tmp = *this;
*this += 1;
return tmp;
}
Date& Date::operator--()
{
*this - 1;
return *this;
}
Date Date::operator--(int)
{
Date tmp = *this;
*this -= 1;
return tmp;
}
//日期-日期,计算两个日期之间相差多少天
int Date::operator-(const Date& d)
{
int flag = 1;
Date max = *this;
Date min = d;
if (*this < d)
{
//赋值为-1的原因:因为这个函数是有顺序的d1-d2,如果遇到d1<d2,也就是小减大,最终返回的结果是个负数,所以说这里要变成-1。
flag = -1;
max = d;
min = *this;
}
//定义一个变量
int n = 0;
// 用循环算两个日期中间的差值
while (min != max)
{
++min;
++n;
}
return n * flag;
}
3.Test.cpp文章来源地址https://www.toymoban.com/news/detail-829692.html
#define _CRT_SECURE_NO_WARNINGS 1
#include <stdio.h>
#include "Date.h"
int main()
{
Date d1(2024, 2, 15);
Date d2 = d1 + 20;
d1.Print();
d2.Print();
bool ret=d1 > d2;
if (ret)
{
d1.Print();
}
d2 += 100;
d2.Print();
d2 -= 100;
d2.Print();
Date d3 = d2 - 10;
d3.Print();
Date d4(2024, 1, 29);
Date d5(2024, 8, 1);
cout << d5 - d4 << endl;
++d5;
d5.Print();
d5++;
d5.Print();
--d5;
d5.Print();
d5--;
d5.Print();
return 0;
}
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