题目：求一个3*3矩阵对角线元素之和
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The blog content is all parallel goods. Those who are worried about being cheated should leave quickly.文章来源：https://www.toymoban.com/news/detail-854076.html
1.程序分析：利用双重for循环控制输入二维数组，再将a[i][i]累加后输出。
2.程序源代码：
main()
{
float a[3][3],sum=0;
int i,j;
printf("please input rectangle element:\n");
for(i=0;i<3;i++)
for(j=0;j<3;j++)
scanf("%f",&a[i][j]);
for(i=0;i<3;i++)
sum=sum+a[i][i];
printf("duijiaoxian he is %6.2f",sum);
}文章来源地址https://www.toymoban.com/news/detail-854076.html
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